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You've probably heard of Einstein's famous equation \(E=mc^2\). This equation has been referenced in hundreds of movies, TV shows, and books as a way of showing a character as smart. But have you ever wondered what this equation actually means? Well, we are going to be covering the concept behind this equation, so you too can be seen as one…
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Jetzt kostenlos anmeldenYou've probably heard of Einstein's famous equation \(E=mc^2\). This equation has been referenced in hundreds of movies, TV shows, and books as a way of showing a character as smart. But have you ever wondered what this equation actually means? Well, we are going to be covering the concept behind this equation, so you too can be seen as one smart cookie!
So let's take a closer look at that equation, shall we?
$$E=mc^2$$
Where:
The key point here is that all objects have an intrinsic amount of energy stored within them. The speed of light is a pretty large number (approximately 3x108 m/s), so even a small particle can have a lot of energy stored within it.
To understand what I mean, let's look at an example.
Let's say we have a cute tuxedo cat that is 3.63 kg (about 8 pounds). How much energy does this cat contain? Well, let’s plug it into our formula:
$$E=mc^2$$
$$E=(3.63\,kg)(3x10^8\frac{m}{s})^2$$
$$E=(3.63\,kg)(9x10^{16}\frac{m^2}{s^2})$$
$$E=3.267x10^17\frac{kg*m^2}{s^2}$$
$$1\,Joule(J)=1\frac{kg*m^2}{s^2}$$
$$E=3.267x10^17\,J$$
For reference, an atomic bomb releases about 1.5·1013 joules, so this is about 22,000 times stronger than that.
While you may now be side-eyeing your furry friend, it isn't actually a ticking time bomb. In reality, it's pretty hard to convert that mass into energy, which is why nuclear weapons are used in warfare instead of cats (or equally heavy objects).
Matter-Antimatter Annihilation
It's incredibly difficult to release all of a species' energy. The only way to do so would be through annihilation. This is a process where the matter and antimatter collide and release all that energy through electromagnetic waves.
For example, if an electron (-e) and a positron (+e) collide, they will annihilate each other and release the stored energy through gamma rays.
Basically, these two species "cancel themselves out" which releases all the stored energy in the matter. However, this process is very uncommon as there isn't much antimatter around.
One of the ways mass is converted to energy is through radioactive decay.
During radioactive decay, an unstable nucleus gives off radiation in the form of energy and/or particles to become more stable
We can use the mass-energy conversion equation to calculate the energy emitted due to the loss of mass through particle emission.
For example, let's calculate the energy loss due to this reaction:
Here we see the decay of a cesium (Cs) atom. It converts one of its neutrons (n) into a proton (p+) and an electron (e-), which is ejected. Since the species is gaining a proton, it becomes barium (Ba).
Every element has a set number of protons called an atomic number. When the atomic number changes (i.e, the number of protons changes), the identity of the element changes,
First, we need to calculate the change in mass. We are going from a radioactive cesium-137 sample (mass 136.907 g/mol) to a neutral barium-137 sample (136.906 g/mol). So the change in mass is:
$$\Delta m=m_{product}-m_{reactant}$$
$$\Delta m=(136.906\frac{g}{mol})-(136.907\frac{g}{mol})$$
$$\Delta m=-0.001\frac{g}{mol}$$
If we assume that there is 1 mol of the sample, there is a -0.001 g or -1x10-6 kg change in mass.
Now we can plug this into our mass-energy conversion formula:
$$\Delta E=\Delta m*c^2$$
$$\Delta E=(-1x10^{-6}\,kg)(3x10^8\frac{m}{s})^2$$
$$\Delta E=-9x10^{10}\,J$$
The amount of energy released here is much, much greater than that of a standard chemical reaction.
Have you ever wondered how the sun produces energy? The answer is nuclear fusion.
Nuclear fusion is the process where smaller atomic nuclei combine to form a heavier nucleus, releasing energy in the process.
In the sun, four hydrogen nuclei fuse to form helium nuclei. If the total mass of the four hydrogen nuclei is 4.03130 amu and the mass of a hydrogen nucleus is 4.00268, what is the total energy amount released?
$$\Delta m=m_{product}-m_{reactants}$$
$$\Delta m=(4.00268\,amu)-(4.03130\,amu)$$
$$\Delta m=-0.02862\,amu$$
Assuming that there is 1 mol of the reactants, the mass change is -0.02862 g or -2.862x10-5 kg
$$\Delta E=\Delta mc^2$$
$$\Delta E=(-2.862x10^{-5}\,kg)(3x10^{8}\frac{m}{s})^2$$
$$\Delta E=2.58x10^12\,J$$
That's a lot of energy!!
Atomic bombs work due to a different process called nuclear fission.
Nuclear fission is the process of splitting a nucleus, which releases energy
The way an atomic bomb works is through a chain fission reaction:
This chain reaction kicks off almost instantaneously, which is why so much energy is released.
While the bombs themselves are massive, the mass change is a lot smaller. For example, one atomic bomb that weighed about 1.86x107 kilograms only converted 0.9 grams of it into energy.
While that may seem small in theory, let's calculate the energy released.
Calculate the energy released when an atomic bond converts 0.9 grams (9x10-4 kg) into energy:
$$\Delta E=\Delta m*c^2$$
$$\Delta E=(9x10^{-4}\,kg)(3x10^8\frac{m}{s})^2
$$\Delta E=8.1x10^{13}\,J$$
For reference, that would be like if you set off over 22,000 tons of TNT.
For each fusion reaction, about 0.002862 amu is converted into energy.
E=mc2
Where E is energy, m is mass, and c is the speed of light
Yes, though it is usually only very small amount
Mass is converted to energy, usually though some form of a nuclear reaction. For example, mass is converted to energy in the sun through nuclear fusion.
Some examples are:
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